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Eccentric reducer layout calculator

In short

A concentric reducer is a right cone frustum: half angle β = atan((D1 − D2) / 2L), generator g = √(L² + (r1 − r2)²). Its flat pattern is a sector of radii Rg = g × r1 / (r1 − r2) and Rg − g, with angle θ = 360° × r1 / Rg; the eccentric one is laid out by triangulation.

Calculation

Example calculated with the tool’s default values.

Inputs

Large end
DN100 · 114.3 × 3.6 mm
Small end
DN50 · 60.3 × 2.9 mm
Type
Concentric
Length
Entered
End-to-end length
150 mm
Pattern diameters
Mean line (OD − wall)
Marks around
16

Results

Half cone angle
10.20°
Ø 114,3Ø 114,3Ø 60,3Ø 60,3L 150L 15010,2°10,2°Ø 114,3Ø 114,3Ø 60,3Ø 60,3L 150L 15010,2°10,2°
Dimensioned drawing of the example

Worked example

Every value in this section belongs to the example, calculated with the tool’s default values.

Other results of the example

Taper
18.0%
End-to-end length
150.0 mm
Shortest generator (seam)
152.3 mm
Longest generator
152.3 mm
Large arc layout radius
316.4 mm
Small arc layout radius
164.1 mm
Sector angle
62.97°
  • Pattern on the mean line (Ø 110.7 / 57.4), no weld allowance.

Step-by-step calculation

  1. Half angle

    β = atan((D1 − D2) / 2L)

    atan(27.0 / 150.0) = 10.20°

  2. Generator

    g = √(L² + (r1 − r2)²)

    √(150.0² + 26.7²) = 152.3 mm

  3. Large arc radius

    Rg = g × r1 / (r1 − r2)

    152.3 × 55.4 / 26.7 = 316.4 mm

  4. Sector

    θ = 360° × r1 / Rg

    360 × 55.4 / 316.4 = 62.97°

Pattern generators

No.Angle (°)Arc on the large end (mm)Arc on the small end (mm)Generator (mm)
10.00.00.0152.3
222.521.711.3152.3
345.043.522.5152.3
467.565.233.8152.3
590.086.945.1152.3
6112.5108.756.4152.3
7135.0130.467.6152.3
8157.5152.278.9152.3
9180.0173.990.2152.3
10202.5195.6101.4152.3
11225.0217.4112.7152.3
12247.5239.1124.0152.3
13270.0260.8135.2152.3
14292.5282.6146.5152.3
15315.0304.3157.8152.3
16337.5326.0169.1152.3

How to use it

  1. Pick the large end and small end pipes: outside diameter and wall thickness.
  2. Pick the type: concentric, or eccentric (one flat side).
  3. Pick the end-to-end length: entered, or EN 10253-2 or ASME B16.9 standard from the large end.
  4. Pick the pattern diameters (mean line or outside diameters) and the number of marks around (8, 12, 16, 24 or 32).
  5. Read the half cone angle (for an eccentric reducer: the sloped side angle).

Frequently asked questions

How do I lay out a concentric reducer?

Work out the generator g = √(L² + (r1 − r2)²), then the large arc radius Rg = g × r1 / (r1 − r2) and the small arc radius Rg − g. The sector to mark has the angle θ = 360° × r1 / Rg. The radii r1 and r2 are taken on the mean line (OD − wall) or on the outside diameters, as you choose.

What pattern for a 114.3 to 60.3 reducer?

Concentric reducer 114.3 × 3.6 to 60.3 × 2.9, 150 mm long, on the mean line (Ø 110.7 / 57.4): half angle atan(27.0 / 150.0) = 10.20°, taper 18 %, generator √(150.0² + 26.7²) = 152.3 mm, large arc 152.3 × 55.4 / 26.7 = 316.4 mm, small arc Rg − g, sector 360 × 55.4 / 316.4 = 62.97°.

How do I make an eccentric reducer layout and template?

An eccentric reducer keeps one flat side: its sloped side makes atan(2Δr / L) with the axis, and the axes are offset by Δr = (D1 − D2) / 2. This oblique frustum is laid out by triangulating the generators, with the seam on the shortest generator: mark the arcs on the large and small ends and the length of each generator.

What is the largest reducer angle?

Above 30°, the calculation warns that EN 13480-3 and ASME B31.3 call for a specific check (knuckle). The small end must be smaller than the large end.

Limits

Indicative results. Pattern with no weld allowance. The standard length comes from the EN 10253-2 or ASME B16.9 tables for the large end: check that this size pair exists in the catalogue, as bought fittings have short straight ends.

Sources

  • Développé d’un tronc de cône : Géométrie : triangulation des génératrices (cône droit ou oblique), joint sur la génératrice la plus courte

Updated · Publisher: The Level Code

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