Piping
Tee and elbow take off calculator
In short
The take-out of a 90° elbow on an equal tee is the sum of the published centre-to-end dimensions along the axis: X = F + A + L + 1 j, with F the tee dimension, A the elbow dimension, L the spool and j the root gap. For a set dimension, the spool to cut is L = X − F − A − 2 j.
Calculation
Example calculated with the tool’s default values.
Inputs
- Pipe
- DN100 · 114.3 × 3.6 mm
- Fitting standard
- EN 10253-2
- Elbow
- 90° long radius (3D / LR)
- Elbow outlet
- In the tee plane
- I know
- The spool (0 = elbow welded to the tee)
- Spool between tee and elbow
- 0 mm
- Root gap
- 0 mm
Results
- Tee axis → outlet axis (vertex)
- 257.0 mm
Worked example
Every value in this section belongs to the example, calculated with the tool’s default values.
Other results of the example
- Spool
- 0.0 mm
- Take-out, elbow welded to the tee
- 257.0 mm
- Equal tee: centre-to-end F
- 105.0 mm
- 90° elbow: centre-to-end A
- 152.0 mm
- Outlet face: distance from tee axis
- 257.0 mm
- Outlet face: offset from branch axis
- 152.0 mm
- Equal tee only: for a reducing tee, take the branch M dimension from the maker’s table.
Step-by-step calculation
Published dimensions
F (tee), A (elbow)
F = 105.0 mm ; A = 152.0 mm
Tee axis → outlet
X = F + A + L + 1 j
105.0 + 152.0 + 0.0 + 0.0 = 257.0 mm
How to use it
- Pick the pipe: outside diameter and wall thickness.
- Pick the fitting standard (EN 10253-2 or ASME B16.9), the elbow (90° long radius, 90° short radius or 45° long radius) and the elbow outlet: in the tee plane or turned 90°.
- Say what you know: the spool between tee and elbow (0 = elbow welded to the tee) or the tee axis → elbow outlet dimension.
- Enter the root gap.
- Read the tee axis → outlet axis (vertex) dimension.
Frequently asked questions
What is the pipe fitting take off formula for a tee and an elbow?
Add the published centre-to-end dimensions along the axis, plus one gap per joint. 90° elbow: X = C + A + L + n j, with n = 1 joint without a spool and 2 with one. 45° elbow: X runs from the tee axis to the elbow vertex, X = C + B + L + n j, and the outlet leaves at 45° from that vertex. The equal tee dimension is called F in EN 10253-2 and C in ASME B16.9.
What is the tee take off for a DN 100 tee and elbow?
114.3 × 3.6 pipe, EN 10253-2 fittings, 90° long radius elbow welded to the tee, no gap: F = 105 mm (equal tee), A = 152 mm (elbow), so 105 + 152 = 257 mm from the tee axis to the outlet axis. The outlet face is 257 mm from the tee axis and 152 mm off the branch axis.
What is the elbow take off formula with a spool?
Choose "Tee axis → elbow outlet dimension" and enter it: the spool to cut is L = X − C − A − 2 j. If the dimension is shorter than the take-out of the elbow welded straight to the tee, the calculation refuses it.
Limits
Indicative results. Equal tee only: for a reducing tee, take the branch M dimension from the maker's table. Dimensions come from the EN 10253-2 and ASME B16.9 tables; outside them, no calculation. 45° EN elbow: take-out taken as R × tan 22.5° (no published dimension read).
Sources
- EN 10253-2:2021+A1:2026 (raccords à souder bout à bout) : Coudes 2D/3D (rayon R), tés égaux (F), réductions (L) ; tableaux Zickwolff, consultés le 08/11/2026 (link)
- Encombrements combinés : Somme des cotes centre-face publiées le long de l’axe, plus un jeu par joint